{ "api_version": "v1", "publisher": { "name": "Manazoo", "url": "https://manazoo.com/" }, "license": "All rights reserved（AI の参照・要約と出典リンクつきの引用は可。転載・再配布・販売は不可）", "terms_url": "https://manazoo.com/terms/", "disclaimer": "内容の正確さには気をつけていますが、すべてが正しいとは限りません。テストや受験の前には、教科書や先生の説明でも確かめてください。間違いを見つけたら意見箱から知らせてください。", "attribution": "事実データの一部は Wikidata（CC0）による。単元の構成は文部科学省「中学校学習指導要領」「高等学校学習指導要領」（政府標準利用規約2.0）。", "kind": "quiz", "unit": { "slug": "electricity", "title": "電気", "url": "https://manazoo.com/high/physics-basic/electricity/" }, "canonical_url": "https://manazoo.com/high/physics-basic/electricity/quiz/", "questions": [ { "id": "q-charge-from-current-2a-5s", "type": "input", "prompt": "導線に2.0Aの電流が流れているとき、5.0秒間に移動する電気量は何Cか。", "choices": null, "answer": "10", "accept": [ "10C" ], "explanation": "電気量q＝It＝2.0×5.0＝10C。", "entities": [ "electric-charge-and-current" ], "verified": true, "placeholder": false }, { "id": "q-current-from-charge-3-2c", "type": "input", "prompt": "0.40秒間に3.2Cの電気量が流れたとき、電流は何Aか。", "choices": null, "answer": "8", "accept": [ "8.0", "8A", "8.0A" ], "explanation": "電流I＝q/t＝3.2÷0.40＝8.0A。", "entities": [ "electric-charge-and-current" ], "verified": true, "placeholder": false }, { "id": "q-electron-flow-vs-current-direction", "type": "choice", "prompt": "電池につないだ回路で、自由電子が移動する向きと、電流の向きの関係について正しいものはどれか。", "choices": [ "常に垂直", "自由電子は動かない", "逆向き", "同じ向き" ], "answer": 2, "accept": [], "explanation": "電流の向きは正の電荷が動く向きと決められており、負の電荷をもつ自由電子は電流と逆向きに移動する。", "entities": [ "electric-charge-and-current" ], "verified": true, "placeholder": false }, { "id": "q-energy-usage-1200w-20min", "type": "input", "prompt": "消費電力1200Wの電気ケトルを20分間使ったときの電力量は何kWhか。", "choices": null, "answer": "0.4", "accept": [ "0.4kWh" ], "explanation": "W＝Pt＝1.2kW×(20/60)h＝0.4kWh。", "entities": [ "joule-heat-and-electric-power" ], "verified": true, "placeholder": false }, { "id": "q-free-electron-current-carrier", "type": "choice", "prompt": "金属中で電流を担っているものは何か。", "choices": [ "陽子", "自由電子", "原子核", "中性子" ], "answer": 1, "accept": [], "explanation": "金属原子から離れ、金属中を自由に動ける自由電子が、電流の運び手になっている。", "entities": [ "electric-charge-and-current" ], "verified": true, "placeholder": false }, { "id": "q-joule-heat-20ohm-3a-10s", "type": "input", "prompt": "抵抗20Ωに3.0Aの電流を10秒間流したときに発生するジュール熱は何Jか。", "choices": null, "answer": "1800", "accept": [ "1800J" ], "explanation": "Q＝I²Rt＝3.0²×20×10＝1800J。", "entities": [ "joule-heat-and-electric-power" ], "verified": true, "placeholder": false }, { "id": "q-parallel-resistance-6-3", "type": "input", "prompt": "6.0Ωと3.0Ωの抵抗器を並列につないだときの合成抵抗は何Ωか。", "choices": null, "answer": "2", "accept": [ "2.0", "2Ω", "2.0Ω" ], "explanation": "並列の合成抵抗は1/R＝1/6.0＋1/3.0＝1/2.0より、R＝2.0Ω。", "entities": [ "resistance-and-resistivity" ], "verified": true, "placeholder": false }, { "id": "q-power-double-resistance-same-current", "type": "choice", "prompt": "電熱線の抵抗を2倍にして、流れる電流の大きさを変えずに保つと、消費電力はどうなるか。", "choices": [ "変わらない", "半分になる", "2倍になる", "4倍になる" ], "answer": 2, "accept": [], "explanation": "P＝I²Rで、電流Iが同じなら、抵抗Rが2倍になるとPも2倍になる。", "entities": [ "joule-heat-and-electric-power" ], "verified": true, "placeholder": false }, { "id": "q-power-from-10v-4a", "type": "input", "prompt": "10Vの電圧をかけると4.0Aの電流が流れる電熱線の消費電力は何Wか。", "choices": null, "answer": "40", "accept": [ "40W" ], "explanation": "P＝VI＝10×4.0＝40W。", "entities": [ "joule-heat-and-electric-power" ], "verified": true, "placeholder": false }, { "id": "q-resistance-same-material-double", "type": "choice", "prompt": "同じ材質の金属線で、長さを2倍、断面積も2倍にすると、抵抗はどうなるか。", "choices": [ "変わらない", "4倍になる", "2倍になる", "半分になる" ], "answer": 0, "accept": [], "explanation": "R＝ρL/Sで、長さLと断面積Sがどちらも2倍になると、R＝ρ(2L)/(2S)＝ρL/Sで変わらない。", "entities": [ "resistance-and-resistivity" ], "verified": true, "placeholder": false }, { "id": "q-resistivity-rho-l-over-s", "type": "input", "prompt": "抵抗率1.0×10⁻⁶Ω・mの金属線で、長さ3.0m、断面積0.50×10⁻⁶m²のものの抵抗は何Ωか。", "choices": null, "answer": "6", "accept": [ "6.0", "6Ω", "6.0Ω" ], "explanation": "R＝ρL/S＝(1.0×10⁻⁶×3.0)÷(0.50×10⁻⁶)＝6.0Ω。", "entities": [ "resistance-and-resistivity" ], "verified": true, "placeholder": false }, { "id": "q-series-resistance-2-6", "type": "input", "prompt": "2.0Ωと6.0Ωの抵抗器を直列につないだときの合成抵抗は何Ωか。", "choices": null, "answer": "8", "accept": [ "8.0", "8Ω", "8.0Ω" ], "explanation": "直列の合成抵抗はR＝R₁＋R₂＝2.0＋6.0＝8.0Ω。", "entities": [ "resistance-and-resistivity" ], "verified": true, "placeholder": false }, { "id": "q-transformer-voltage-20v-100-500", "type": "input", "prompt": "一次コイル100回、二次コイル500回の変圧器の一次側に20Vを入力したとき、二次側の電圧は何Vか。", "choices": null, "answer": "100", "accept": [ "100V" ], "explanation": "V₂＝V₁×(N₂/N₁)＝20×(500/100)＝100V。", "entities": [ "transformer-and-power-transmission" ], "verified": true, "placeholder": false }, { "id": "q-transmission-current-10000w-100v", "type": "input", "prompt": "10000Wの電力を電圧100Vで送るとき、送電線に流れる電流は何Aか。", "choices": null, "answer": "100", "accept": [ "100A" ], "explanation": "I＝P/V＝10000÷100＝100A。", "entities": [ "transformer-and-power-transmission" ], "verified": true, "placeholder": false }, { "id": "q-transmission-loss-100a-0-5ohm", "type": "input", "prompt": "100Aの電流が流れる、抵抗0.50Ωの送電線で生じる送電損失は何Wか。", "choices": null, "answer": "5000", "accept": [ "5000W" ], "explanation": "送電損失はI²R＝100²×0.50＝5000W。", "entities": [ "transformer-and-power-transmission" ], "verified": true, "placeholder": false }, { "id": "q-transmission-loss-voltage-10x", "type": "choice", "prompt": "送る電力を変えずに送電電圧を10倍にすると、送電線で生じる送電損失（I²R）は何倍になるか。", "choices": [ "変わらない", "1/100倍", "1/10倍", "10倍" ], "answer": 1, "accept": [], "explanation": "電力一定ならI＝P/Vより電流は1/10になる。送電損失はI²Rなので、(1/10)²＝1/100になる。", "entities": [ "transformer-and-power-transmission" ], "verified": true, "placeholder": false } ] }